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xsl to find and replace a string

Given text, use XSLT and regex to find an ID and a URL then replace the URL with a given URL+the ID.

Details:

Given the RSS data below, for each item use only XSL to find the ID ("ID12345" or "ID00000" in this example) and replace the URL ("[url removed, login to view]" in this example) with the new URL "https://[url removed, login to view]" + the ID ("https://[url removed, login to view]" in this example)

sample source rss file to transform attached

Some regex you can use. This seems to work but I'm open to using different regex if you need.

for ID: "ID....."

for URL: "\bhref=.([^\x22\r\n]+\x22)"

Compétences : XSLT

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Concernant l'employeur :
( 2 commentaires ) redmond, United States

N° du projet : #1051993

Décerné à :

kamilzola

I did it just to see if I can. More in PM.

35 $ USD en 0 jours
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abhishekmitro

I have it ready

35 $ USD en 0 jours
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1.1

4 freelance ont fait une offre moyenne de 40 $ pour ce travail

ankit15

Gone is the time when only unix ,perl could use regex.XSLT can also now. Assured work. Help and support through conversation at skype or yahoo.

50 $ USD en 1 jour
(0 Commentaires)
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prjdevelop

It will be completed in 5 hrs.

40 $ USD en 2 jours
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