Access to computer and suitable programming tools, e.g. MATLAB, Excel/Visual Basic, C , etc.
1. Develop 3-Phase Radial Load-flow Program & set up Feeder Model.
a) Develop a radial load flow program and set up a uniformly distributed load feeder model of 10
equal loads. Total feeder load = 100 kVA (3-phase), at peak, operating at 0.9 power factor
lagging. Total feeder length = 500 m. The cable impedance = 0.315 +j0.365
2. Perform Radial Load-flow with Embedded Solar.
a) With the loads the same, allow for embedded solar at each node. Use the residential load
curve. The solar sources are generators, so they will be represented by negative real power
loads. Assume they will operate at unity power factor. Run the load flow again for 5 pm
afternoon peak load conditions. The embedded solar = 0.3 * peak load. Record your results.
Comment on the improvement in feeder current and voltage drop.
b) Now, run the load flow for residential midday light load conditions, when embedded solar =
peak load value, but the midday load is 0.3 * peak load (i.e. embedded solar = 3 * midday load).
Record your results. Comment on the feeder current and voltage drop. What happens to the
voltage drop? What is the voltage spread at the end of the feeder (node #10) from midday to
evening peak situations with solar present?
3. Perform Radial Load-flow with Embedded Solar & Energy Storage Units.
a) Using the same peak residential loads as before, consider one or more storage units being
turned on over the peak period, so that they can lop 30% off the daily peak load. From the
residential daily load curve in the Addendum, calculate by numerical integration (counting the
squares) the total storage unit energy capacity required to achieve a 30% peak load lop for the
residential load curves for the whole LV feeder. (iii) What is the maximum load reduction
possible through the use of energy storage and the energy required?
b) Run the load flow for the 30% peak lop case, assuming the storage is split into 10 equal storage
units of same total capacity as in a). Assume the storage units act as generators running at unity
power factor. Compare to the base peak load case in section 1 b). Comment on improvements
in feeder current and voltage drop.
c) Now assume the storage is available in only one unit of same total capacity as above. Perform
several runs of your load flow with the storage unit at several locations, including last node
(#10), first node (#1) and also at several other positions along the feeder. What yields the best result, in terms of feeder current and voltage drop? How does this compare with section 3 b)
transformer 1 2 9 10
415 V radial feeder
MV 415 V bus
Cable impedance Z = 0.315+j0.365 ohms/ph/km
Fig 1 – The Test Low Voltage 10-node Radial Distribution Feeder
Power Systems Plan & Economics Assignment 2020
ohms/phase/kilometre. The peak load refers to the residential load curve at about 5 pm (refer
b) Run your load flow. Are current and voltage constraints being exceeded? Current constraint =
200 A/phase; voltage constraint = 415 V +/- 5%. If the supply end voltage was raised above 415
V would this solve any peak load?
c) Now, run the load flow for light-load conditions = 30% of peak load conditions (refer to the
residential load curve at about 11 am). Are voltage constraints being exceeded? Record all your
feeder current (supply end) and voltage drops. If the supply volts is raised as in 1(b) are voltages
too high in light-load conditions?
d) The load at node #10 is a large induction motor and is a fluctuating load. Its starting current is 5
times its normal running load (as in part 1(b)) and starting power factor is 0.4 lagging. Re-run
your load flow and determine the change in voltage drop, at both node #9 and node #10. Is the
voltage drop at node #10 > 10%? Is the voltage drop at node #9 (the “common point of
coupling”) > 4%?
3 freelances font une offre moyenne de 80 $ pour ce travail
I already have a code that can do Load flow analysis in matlab . I have the same code in python as well. These codes are excel compatible. i can deliver you the output in 8 to 10 days from now.
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