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Help calculating NPV

I need quick turn around, preferably in 1-2 hours.

Compétences : Mathématiques

Voir plus : homework help due hours, hours turn around, hours turn time project, calculating lost man hours, grammar quick turn around, quick turn around translation

Concernant l'employeur :
( 0 commentaires ) mahdia, United Kingdom

N° du projet : #8510321

Décerné à :

uttamsaha1981

I am ready to do the job for you and can do it nicely with very good output in time. Please, check reviews of my past projects.

60 $ USD en 1 jour
(34 Commentaires)
4.4

7 freelance ont fait une offre moyenne de 89 $ pour ce travail

DavidSolomon1991

Please, visit my profile to make an appropriate decision to award the project to a right person. The link of my profile is https://www.freelancer.com/u/DavidSolomon1991.html

100 $ USD en 3 jours
(98 Commentaires)
5.7
anshulbajaj

Good Day, I can easily do this for you. Though the turnaround time is a little problem considering it is already 1:30am in India. But you get it first thing in the morning. Cheers. AB

100 $ USD en 1 jour
(6 Commentaires)
3.1
elqueabandona

Hello, my name is Cristian, I have a degree in Business and work with excel every day. I have much experience with spreadsheets, formulas, models and macros. Check my reviews. They speak for themselves. Best regard Plus

150 $ USD en 3 jours
(1 Commentaire)
3.0
hussain62333

sir this is an engineering economy problem .i will do it for you using the present worth analysis and will answer this .i am a senior year mechanical engineering student .llet me know if you wanna hire

45 $ USD en 1 jour
(0 Commentaires)
0.0
farahkhattab

As a chemical engineer I took some courses on management and choosing the good cost and great quality .. there fore i'll try helping you in taking your decision by making a cash flow diagram for each option .

77 $ USD en 3 jours
(0 Commentaires)
0.0
amahrous95

I have more than 5 years of experience.I am experienced person to do the work with accuracy and time

88 $ USD en 2 jours
(0 Commentaires)
0.0