Answer this question in Scheme RSR5
; A positive integer n > 1 is said to be +-perfect if it is the sum of its proper divisors. Thus 6 is +-perfect,
; as its proper divisors are 1, 2 and 3. The next +-perfect number is 28, given as 1 + 2 + 4 + 7 + 14.
; Similarly, a positive integer n > 1 is said to be *-perfect if it is the product of its proper divisors. Thus 6 and
; 8 are *-perfect.
; We want a single program, op-perfect, which can be used to test whether a number is +-perfect or *-perfect, depending on
; whether op = + or op = *, respectively.
; Specify, design, develop, code and prove correct an ITERATIVE Scheme program op-perfect? which inputs an integer n > 1, an
; operator op, and which outputs #t if n is op-perfect and #f otherwise. USE A LOCAL FUNCTION, and try to make your program
; reasonably efficient.
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